Swap two array elements in MIPS -


i have swap 2 array elements. i've done this, in lw $t2, 0($t0) #$t2 = array [i] starts crashing , don't know how fix it.

here code:

.data  vector: .word   10, 20, 3, 20, 20, 50, 560, 100, 1005, 10 j:      .word   0 i:      .word   0 cad:    .asciiz     "introduce el indice del primer elemento:\n" cad2:   .asciiz     "introduce el indice del segundo elemento:\n"       .text  main:      la $a1, vector  #cargo en a1 la dirección base del vector     la $a2,       #cargo en a2 el índice     la $a3, j       #cargo en a3 el índice j     move $a1, $zero  #inicializo cero     move $a2, $zero  #inicializo j cero      li $v0,4        #imprimo un string     la $a0, cad     syscall      li $v0, 5       #leo el primer índice     syscall      move $a1, $v0   #muevo el entero de v0 a1     li $v0,4        #imprimo un string     la $a0, cad2     syscall      li $v0,5        #leo el segundo índice     syscall      move $a2, $v0   #muevo el entero de v0 a2      sll $t0, $a2,2      # $t0 = i*4     add $t0, $t0, $a1   # $t0 contiene la dirección del vector[i]     sll $t1, $a3, 2     # $t1 = j*4     add $t1, $t1, $a1   # $t1 contiene la dirección del vector[j]      lw $t2, 0($t0)      #$t2 = array [i]     lw $t3, 0($t1)      #$t3 = array[j]     sw $t2, 0($t1)      #array[j]=array[i]     sw $t3, 0($t0)      #array[i]=previous values of array[j]     syscall           li $v0,1     la $a0, vector     syscall     li $v0, 10     syscall

thanks help, , sorry if i've said wrong, see i'm spain.

looking @ code see 2 issues:

you using $a1 store base address of vector, $a1 used argument syscalls. in code , see overwriting $a1 syscall. suggest use other register store base address of vector.

you overwriting $a1 when want initialize index variables (i , j), according code should $a2 , $a3.


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