bash - IF statement inside a loop in linux terminal not working -


currently trying execute bash file in crontab. however, command not working, command.

for ip in $(seq 3 80); ip2 in $(seq 9 254); count=$(ping -c 1 192.168.$ip.$ip2 | grep icmp* | wc -l) if [ $count -eq 0 ]; echo "host unreachable" else php /var/www/phpfile.php 192.168.$ip.$ip2 > 192.168.$ip.$ip2.txt; done; done

the error console showing when execute command this:

if: command not found

i checked spaces between brackets, tried remove them, none of solutions have worked. can please tell me wrong command? missing?

thank in advance.

you missing fi , ;, try this:

for ip in $(seq 3 80); ip2 in $(seq 9 254); count=$(ping -c 1 192.168.$ip.$ip2 | grep icmp* | wc -l); if [ $count -eq 0 ]; echo "host unreachable"; else php /var/www/phpfile.php 192.168.$ip.$ip2 > 192.168.$ip.$ip2.txt;fi; done; done

it's better (for readability) break codes multiple lines insead of putting them in single line:

for ip in $(seq 3 80);  ip2 in $(seq 9 254);    count=$(ping -c 1 192.168.$ip.$ip2 | grep icmp* | wc -l)   if [ $count -eq 0 ];     echo "host unreachable"    else php /var/www/phpfile.php 192.168.$ip.$ip2 > 192.168.$ip.$ip2.txt;   fi  done done

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