Using jQuery shake effect on document ready -


i'm trying have element on page shake when page loads. shake briefly(about 2 seconds) when username , password incorrect on sites.

here have tried.

       <div id="login_wrapper">           <div id="login_header"><div id="header_title">enter login details below</div> </div>           <div id="login_input_wrapper">           <div id="username_wrapper">             <div id="username_label"><h3>username</h3></div><div id="username_input"><input type="text" class="text_field" id="login_username" name="login_username" placeholder="username123"></div>           </div>          <div id="username_wrapper">            <div id="username_label"><h3>password</h3></div><div id="username_input"><input type="password" class="text_field" id="login_password" name="login_password" placeholder="itsasecret"></div>          </div>         <div id="" class=""> <button class="login_button" value="submit"> login </div>       </div>     </div>      </div>    <script type="text/javascript">  $( document ).ready(function() {   $( "#login_wrapper" ).effect( "shake" ); });    </script>

i have placed before end of body in document, getting no response. i'm new jquery, can me see whats wrong code please?

.effect() part of jqueryui. have load jquery , jqueryui (in order) make work.

check jsfiddle


Comments

Post a Comment

Popular posts from this blog

c++ - Difference between pre and post decrement in recursive function argument -

i have following sample code used pre-decrement void function(int c) { if(c == 0) { return; } else { cout << "dp" << c << endl; function(--c); cout << c << endl; return; } } this function give output input 4 : dp3 dp2 dp1 dp0 0 1 2 3 but when use post decrement void function(int c) { if(c == 0) { return; } else { cout << "dp" << c << endl; function(c--); cout << c << endl; return; } } output goes in infinite loop dp4 can explain me in detail why happens ? this happens because function(c--) called same value of c , when finishes c decremented. recursively called, hence called same value no chance of return , hit stack overflow error. assume this, int x = 1, y = 0; y = x++ result y == 1 , x == 2. if y = ++x , bot x , y 2.
Read more

php - Nothing but 'run(); ' when browsing to my local project, how do I fix this? -

i added new project. made mistake in projectname.conf file in sites-available apache2, led me reinstalling apache2. after reinstalling , re-enabling projects on every page of every project .. <body> run(); </body> .. i've run composer update, restarted service, restarted pc, checked config files, tried disabling new project. there nothing in error log, , access.log: 127.0.0.1 - - [15/may/2015:01:40:47 +0200] "get / http/1.1" 304 181 "-" "mozilla/5.0 (x11; ubuntu; linux x86_64; rv:38.0) gecko/20100101 firefox/38.0" maybe i'm forgetting apache2 reinstall? don't think did different last time installed it. looks haven't setup php correctly. take @ this great guide , maybe you're forgetting link php config apache2.
Read more

php - How can I echo out this array? -

i don't know how go grabbing data in variable , put foreach loop. class tree{ private $info = array( array('name'=>'jim','state'=>'nu','company'=>'nu','phone'=>array('cell'=>'5615111111','office'=>'5611111111'),'email'=>array('primary'=>'exs@example.com','ex@there.com')), array('name'=>'joe smith','city'=>'phoenix','phone'=>'4805551111','email'=>'jsmith@some_email.com'), array('name'=>'john doe','city'=>'chandler','company'=>'doe co.','email'=>array('jdoe@gmail.com','personal'=>'email@email.com'),'phone'=>'6025550002') ); } if you're inside of class, can access private variable using $this->variablename . example, i
Read more