mysql - Select values by one parameter and complete table with other -


really hard explain problem in title. have table of translations multiple languages in looks this

+---------------+----------------------------------+----------+ | name          | translation                      | language | +---------------+----------------------------------+----------+ | translation_1 | text translation n.1 | en       | +---------------+----------------------------------+----------+ | translation_2 | text translation n.2 | en       | +---------------+----------------------------------+----------+ | translation_3 | text translation n.2 | en       | +---------------+----------------------------------+----------+ | translation_2 | toto je text pre preklad č.2     | sk       | +---------------+----------------------------------+----------+

now need fetch translations language 'sk' can't sure there translations languages want achieve fetch language 'sk' , complete translations language 'en' (which default language , have translations).

this should result 

+---------------+----------------------------------+----------+ | name          | translation                      | language | +---------------+----------------------------------+----------+ | translation_1 | text translation n.1 | en       | +---------------+----------------------------------+----------+ | translation_2 | toto je text pre preklad č.2     | sk       | +---------------+----------------------------------+----------+ | translation_3 | text translation n.2 | en       | +---------------+----------------------------------+----------+

thanks advice!

considering each translation exists "en", can do

select   en.name,   ifnull(sk.translation, en.translation) translation,   ifnull(sk.language, en.language) language translation en   left join translation sk on en.name = sk.name , sk.language = "sk" en.language = "en"

you select english translations , left join swedish translations. translation , language column, state prefer swedish, otherwise english.


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