bash - Can't read file content to variable via cronjob -


my program try read content of file in variable.

root@pi:/tmp> cat /bin/dnsupdate #!/bin/sh  set -xv  ip="$(cat /tmp/ip)" echo $ip exit 0

when run program in shell, works perfectly.

root@pi:/tmp> dnsupdate  ip="$(cat /tmp/ip)" +/bin/dnsupdate:5> ip=+/bin/dnsupdate:5> cat /tmp/ip +/bin/dnsupdate:5> ip=92.192.52.164 echo $ip +/bin/dnsupdate:6> echo 92.192.52.164 92.192.52.164 exit 0 +/bin/dnsupdate:7> exit 0

now adding cronjob , logging script output.

root@pi:/tmp> crontab -l #m   h    d    m    w    cmd *    *    *    *    *    dnsupdate >>/tmp/dns 2>>/tmp/dns 
root@pi:/tmp> cat dns  ip="$(cat /tmp/ip)" +/bin/dnsupdate:5> ip=+/bin/dnsupdate:5> cat /tmp/ip +/bin/dnsupdate:5> ip='' echo $ip +/bin/dnsupdate:6> echo  exit 0 +/bin/dnsupdate:7> exit 0

also tried #!/bin/zsh shebang since default shell zsh , stuff ip=$(</tmp/ip) still no luck. why there no content in variable when script runs via cron?


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