sql - find a date when sales for id reach some level -


i need find date, when sum paid every user exceeded $100. have table in below format:

+----------------------------------------+------------+----+ |     pay_date, user_id, transaction_sum |            |    | +----------------------------------------+------------+----+ |     01/01/14, a1,      $2              |            |    | |     01/01/14, a2,      $5              |            |    | |     01/01/14, b1,      $10             |            |    | |     03/01/14, a1,      $2              |            |    | |     03/01/14, b1,      $2              |            |    | |     03/01/14, c1,      $5              |            |    | |     04/01/14, a3,      $2              |            |    | |     04/01/14, a3,      $20             |            |    | |     04/01/14, c1,      $5              |            |    | +----------------------------------------+------------+----+     ...  (ordered pay_date)

i'd have in result table this:

user_id, pay_date a1,      03/03/14 a2,      30/03/14 a3,      22/05/14 b1,      01/01/15 c1,      12/10/14

the total cumulative amount of money paid users exceed $100, need date when exceeded. other users not exceed, don't need them in table.

apologies if haven't explained enough thanks

afaik redshift supports windowed aggregate functions:

select user_id, min(pay_date)   (    select pay_date, user_id,       sum(transaction_sum) -- cumulative sum based on pay_date       on (partition user_id             order pay_date             rows unbounded preceding) cum_sum    tab  ) dt cum_sum > 100 -- rows cumulative sum exceeds limit  group user_id

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