Printing the value of a pointer in C -

int main() { int *i,*j;  printf("%u",i); }

the above program result in output 0

int main() {  int *i,*j;  j=i; printf("%u",i); }

but

the above program result in non zero. why?

both pointers not initialized initial value indeterminate. accessing uninitialized pointer undefined behavior.

moreover use p conversion specifier print pointer value (and yes cast required) u requires unsigned int argument :

printf("%p\n", (void *) i);

Lix