mysql - How to use array in select query where statement in php? -


i have code this:

$sql11 = "select room_no guestrocordtransc roomtype='".$roomtype."'"; $retval11 = mysql_query( $sql11, $conn ); while($row11 = mysql_fetch_array($retval11,mysql_assoc)) {      $cid_room=$row11['roomno'];  }

here i'm getting array of room numbers, stored in $cid_room.

now, need $cid_room in select query fetch particular room_no not in guestrocordtransac.

my second query looks this:

$sql = "select room_no  roominfo room_no  not in( select roomno  guestrocordtransac  roomtype='".$roomtype."'  between '".$check_in."'  , '".$check_out."'  , cid='".$cid_room."')  , roomtype='".$roomtype."'";

is possible give array value ($cid_room) in query, check value.

if $cid_room not multi-dimensional array, use array in select query that:

"select room_no roominfo room_no not in (".implode(',',$cid_room).") , roomtype='".$roomtype."'";

but ' m not sure works in case.


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