Compile c file by source code -


i'm writing code got path c file, , want compile file program code. meaning compile not in command line like: 

gcc -o a.out file.c

there way it?

if trying compile c source file in programmatic manner, can try this:

execlp("gcc", "gcc", "file.c", "-o", "a.out", null);

execlp has advantage of searching dirs stored in environment $path find required executable. returns -1 if call fails. don't forget #include <unistd.h> work.

you can away simple call:

system("gcc file.c -o a.out");

this requires #include <stdlib.h> , execute gcc invoking /bin/sh.


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