oracle - SQL: MAX(id) in where clause subquery with group by -


i have query , subquery in query, should give string of dates of different rows in group (group by).

this works:

enter image description here want string in report other rows same max(id) because can't use max(inner.id) min(outer.id) in clause of inner query don't know how that, suggestion?

my code (simple version):

select   (select listagg(to_timestamp('1970/01/01 00:00:00 ', 'yyyy/mm/dd hh24:mi:ss')  +  timestamp/86400, ', ') within group (order id) timestamps tbl inner   max(inner.id) max(outer.id)  ,  mrdin.timestamp between  time , time  group customer having count (2) > 1) alias  tbl outer  timestamp between  time ,  time  group    customer;

enter image description here

i want strings (timestamp) of first picture in dates column of second picture using max(id) of both compare. can't because of can't user max() function in clausule of inner select.

i don't understand trying do, work you?

select (select listagg(to_timestamp('1970/01/01 00:00:00 ', 'yyyy/mm/dd hh24:mi:ss')  + timestamp/86400, ', ') within group (order id) timestamps           tbl inner         ,    inner.timestamp between time , time         group customer          having count (2) > 1         , max(inner.id) = outer_id        ) alias  ( select max(id) outer_id     tbl outer   timestamp between time , time   group customer );

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