java - Error when trying to run app [Android] -


okay im trying make app has 4 images on front page. when click each image want window pop in case doesn't work @ app craches in how :/

05-14 19:10:08.981    2276-2276/com.example.flygplanappen.peterjapp e/androidruntime﹕ fatal exception: main     process: com.example.flygplanappen.peterjapp, pid: 2276     android.content.activitynotfoundexception: no activity found handle intent { act=com.example.flygplanappen.peterjapp.flygos2 }             @ android.app.instrumentation.checkstartactivityresult(instrumentation.java:1765)             @ android.app.instrumentation.execstartactivity(instrumentation.java:1485)             @ android.app.activity.startactivityforresult(activity.java:3736)             @ android.app.activity.startactivityforresult(activity.java:3697)             @ android.app.activity.startactivity(activity.java:4007)             @ android.app.activity.startactivity(activity.java:3975)             @ com.example.flygplanappen.peterjapp.flygos$1.onclick(flygos.java:24)             @ android.view.view.performclick(view.java:4756)             @ android.view.view$performclick.run(view.java:19749)             @ android.os.handler.handlecallback(handler.java:739)             @ android.os.handler.dispatchmessage(handler.java:95)             @ android.os.looper.loop(looper.java:135)             @ android.app.activitythread.main(activitythread.java:5221)             @ java.lang.reflect.method.invoke(native method)             @ java.lang.reflect.method.invoke(method.java:372)             @ com.android.internal.os.zygoteinit$methodandargscaller.run(zygoteinit.java:899)             @ com.android.internal.os.zygoteinit.main(zygoteinit.java:694)

you're doing this:

button button = (button) findviewbyid(r.id.imageview4)

if in xml layout, you'll find imageview4 defined imageview, cannot cast button. imageview subclass of view, , button subclass of view (textview, actually), imageview not subclass of button, , therefore can't cast button that.

however, onclick method work on view, not button.

so, is:

view button = findviewbyid(r.id.imageview4);

or, if need access methods imageview:

imageview imageview = (imageview) findviewbyid(r.id.imageview4);

Comments

Post a Comment

Popular posts from this blog

c++ - Difference between pre and post decrement in recursive function argument -

i have following sample code used pre-decrement void function(int c) { if(c == 0) { return; } else { cout << "dp" << c << endl; function(--c); cout << c << endl; return; } } this function give output input 4 : dp3 dp2 dp1 dp0 0 1 2 3 but when use post decrement void function(int c) { if(c == 0) { return; } else { cout << "dp" << c << endl; function(c--); cout << c << endl; return; } } output goes in infinite loop dp4 can explain me in detail why happens ? this happens because function(c--) called same value of c , when finishes c decremented. recursively called, hence called same value no chance of return , hit stack overflow error. assume this, int x = 1, y = 0; y = x++ result y == 1 , x == 2. if y = ++x , bot x , y 2.
Read more

php - Nothing but 'run(); ' when browsing to my local project, how do I fix this? -

i added new project. made mistake in projectname.conf file in sites-available apache2, led me reinstalling apache2. after reinstalling , re-enabling projects on every page of every project .. <body> run(); </body> .. i've run composer update, restarted service, restarted pc, checked config files, tried disabling new project. there nothing in error log, , access.log: 127.0.0.1 - - [15/may/2015:01:40:47 +0200] "get / http/1.1" 304 181 "-" "mozilla/5.0 (x11; ubuntu; linux x86_64; rv:38.0) gecko/20100101 firefox/38.0" maybe i'm forgetting apache2 reinstall? don't think did different last time installed it. looks haven't setup php correctly. take @ this great guide , maybe you're forgetting link php config apache2.
Read more

php - How can I echo out this array? -

i don't know how go grabbing data in variable , put foreach loop. class tree{ private $info = array( array('name'=>'jim','state'=>'nu','company'=>'nu','phone'=>array('cell'=>'5615111111','office'=>'5611111111'),'email'=>array('primary'=>'exs@example.com','ex@there.com')), array('name'=>'joe smith','city'=>'phoenix','phone'=>'4805551111','email'=>'jsmith@some_email.com'), array('name'=>'john doe','city'=>'chandler','company'=>'doe co.','email'=>array('jdoe@gmail.com','personal'=>'email@email.com'),'phone'=>'6025550002') ); } if you're inside of class, can access private variable using $this->variablename . example, i...
Read more