sql server - T sql order by 2 rows according to different dates -


i have table called "customers"

customers table has below columns

companyname varchar(100)     productname varchar(100)     createddate datetime     salesprice money

i have below data in customer table

companyname (column) - productname (column)  -  createddate (column) -   salesprice (column)                      b                        2015-01-02 00:00:00.000  419,10       c                      d                        2014-04-20 00:00:00.000  30,10                             b                        2014-01-02 00:00:00.000  60,00        c                      d                        2015-04-20 00:00:00.000  540,00

i want select data below. need order createddate less more like

createddate 2014  createddate 2015  createddate 2014  createddate 2015

result must below (2014-2015 ordering)

a                      b                  2014-01-02 00:00:00.000  60,00  (this 2014)                      b                  2015-01-02 00:00:00.000  419,10 (this 2015)     c                      d                  2014-04-20 00:00:00.000  30,10  (this 2014)   c                      d                  2015-04-20 00:00:00.000  540,00 (this 2015)

question:

how can select customer table

first 2014 date 2015 date if exists more 2016 etc.. if companyname same , productname same result in above side ?

what need add order in query.

select * customers order companyname, productname, createddate;

updated:

select  companyname, productname, createddate, row_number() on (partition year(createddate)                                    order year(createddate)) rownumber    customers order rownumber, year(createddate)

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