java - Find the nearest/closest value in a sorted List -


i wondering if possible find closest element in list element that not there.

for example if had values [1,3,6,7] , looking element closest 4, should return 3, because 3 biggest number in array, smaller 4.

i hope makes sense, because english not native language.

if array sorted can modified binary search in log n operations: 

    public static int search(int value, int[] a) {          if(value < a[0]) {             return a[0];         }         if(value > a[a.length-1]) {             return a[a.length-1];         }          int lo = 0;         int hi = a.length - 1;          while (lo <= hi) {             int mid = (hi + lo) / 2;              if (value < a[mid]) {                 hi = mid - 1;             } else if (value > a[mid]) {                 lo = mid + 1;             } else {                 return a[mid];             }         }         // lo == hi + 1         return (a[lo] - value) < (value - a[hi]) ? a[lo] : a[hi];     }

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