Only else part is being executed in If-else statement in matlab -


i'm working on counting numbers using if-else statement. i'm getting result, it's executing else part , not looking @ other part.

this code i'm working with

i = 0; j = 0;  if sum( abs( f1(:) - f2(:))) == 0.0    = + 1; else    j = j + 1; end if sum(abs(f2(:) - f3(:))) == 0.0    = + 1; else    j = j + 1; end if sum(abs(f3(:) - f4(:))) == 0.0    = + 1; else     j = j + 1;    end  msgtext = sprintf('matching = %d',i); h = msgbox(msgtext);  msgtxt = sprintf(' not matching = %d',j); h = msgbox(msgtxt);

any suggestions?

thanks in advance!

your question extremely vague i'm going pretend asked 1 of ifs:

if sum( abs( f1(:) - f2(:))) == 0.0    = + 1; else    j = j + 1; end

i think there fair chance ever fall else clause because trying equate floating point numbers, , bad idea due precision errors. depends on nature of f1 , f2, doubles, how calculated etc have given no indication of in question. if want understand why can't equate floating point numbers (or expect there difference equal 0) must read what every computer scientist needs know floating-point arithmetic

rather try if sum( abs( f1(:) - f2(:))) < tol tol (i.e. tolerance) tiny number (e.g. eps, choose number orders of magnitude less application produce.).


Comments

Post a Comment

Popular posts from this blog

c++ - Difference between pre and post decrement in recursive function argument -

i have following sample code used pre-decrement void function(int c) { if(c == 0) { return; } else { cout << "dp" << c << endl; function(--c); cout << c << endl; return; } } this function give output input 4 : dp3 dp2 dp1 dp0 0 1 2 3 but when use post decrement void function(int c) { if(c == 0) { return; } else { cout << "dp" << c << endl; function(c--); cout << c << endl; return; } } output goes in infinite loop dp4 can explain me in detail why happens ? this happens because function(c--) called same value of c , when finishes c decremented. recursively called, hence called same value no chance of return , hit stack overflow error. assume this, int x = 1, y = 0; y = x++ result y == 1 , x == 2. if y = ++x , bot x , y 2.
Read more

php - Nothing but 'run(); ' when browsing to my local project, how do I fix this? -

i added new project. made mistake in projectname.conf file in sites-available apache2, led me reinstalling apache2. after reinstalling , re-enabling projects on every page of every project .. <body> run(); </body> .. i've run composer update, restarted service, restarted pc, checked config files, tried disabling new project. there nothing in error log, , access.log: 127.0.0.1 - - [15/may/2015:01:40:47 +0200] "get / http/1.1" 304 181 "-" "mozilla/5.0 (x11; ubuntu; linux x86_64; rv:38.0) gecko/20100101 firefox/38.0" maybe i'm forgetting apache2 reinstall? don't think did different last time installed it. looks haven't setup php correctly. take @ this great guide , maybe you're forgetting link php config apache2.
Read more

php - How can I echo out this array? -

i don't know how go grabbing data in variable , put foreach loop. class tree{ private $info = array( array('name'=>'jim','state'=>'nu','company'=>'nu','phone'=>array('cell'=>'5615111111','office'=>'5611111111'),'email'=>array('primary'=>'exs@example.com','ex@there.com')), array('name'=>'joe smith','city'=>'phoenix','phone'=>'4805551111','email'=>'jsmith@some_email.com'), array('name'=>'john doe','city'=>'chandler','company'=>'doe co.','email'=>array('jdoe@gmail.com','personal'=>'email@email.com'),'phone'=>'6025550002') ); } if you're inside of class, can access private variable using $this->variablename . example, i...
Read more