string - Efficicient way for Java pattern Matching -


what best , fastest way check if string matches like:"ab+space+number+anything eg: "ab 1234 defg" looking efficient way, going compare thousands of transaction per minute.

use string.matches function uses regex string matching.

string.matches("ab \\d+.*");                 ^ ^  ^ ^                 | |  | |_                ab | num                   |                 space

if want space after number, use 

"ab \\d+ .+"

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