ORACLE SQL: Show the department name, id, and # of employees of the dept. that has the least # of employees -


note, homework question!

show department number, department name, , number of employees working in department has least number of employees.

i can figure out how many employees each department has, how show department least number of employees?

select employees.department_id, departments.department_name, count(employee_id) employees join departments on employees.department_id = departments.department_id group employees.department_id, departments.department_name;

what need having clause, allows apply condition after group by clause applied. in other words, allows apply condition on aggregate expression:

select employees.department_id, departments.department_name, count(employee_id) employees join departments on employees.department_id = departments.department_id group employees.department_id, departments.department_name; having count(*) > 5 -- here!

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