c++ - Dereferencing addresses of one type as addresses of another -

this question applies coding language allows users manipulate pointers, asking in regards c++.

suppose have 2 types of same size, example, suppose (long) , (int) both 8 bytes in size. let's declare (long) , (int):

long somelong = 10; int someint = 20; 

suppose address of somelong , someint x , y, respectively, , suppose in hexadecimal, y = x + 80. if try manually move x y , dereference it, not value of 20 expect. why this?

cout << &somelong + 10     cout << &someint             // these 2 return same starting address location  cout << *(&somelong + 10)    // dereferences int long, not return 20! 

i believe it's technically implementation dependent, there's no guarantee.

on other hand, in experience using differently typed pointers same memory in practice tends work way expect to.

and this:

#include <iostream> using namespace std;  int main() {     long somelong = 10;     int someint = 20;      cout << &somelong + 1 << '\n';     cout << &someint << '\n';      cout << *(&somelong + 1);      return 0; } 

works me such outputs 20.

to hope answer why doesn't you, have see actual code. , know compiler you're using.