matplotlib - Python & Matplot: How can I draw a simple shape by points? -
i want draw simple shape points, this:
rectangle = [(0,0),(0,1),(1,1),(1,0)] hexagon = [(0,0),(0,1),(1,2),(2,1),(2,0),(1,-1)] l_shape = [(0,0),(0,3),(1,3),(1,1),(3,1),(3,0)] concave = [(0,0),(0,3),(1,3),(1,1),(2,1),(2,3),(3,3),(3,0)] points in [rectangle, hexagon, l_shape, concave]: # 1. can rid of zip? plot directly points # 2. how can make shape complete? xs, ys = zip(*points) plt.plot(xs, ys, 'o') plt.plot(xs, ys, '-') automin, automax = plt.xlim() plt.xlim(automin-0.5, automax+0.5) automin, automax = plt.ylim() plt.ylim(automin-0.5, automax+0.5) # can display shapes 2 in 1 line? plt.show() my question 
- how can rid of
*zip? mean, directyly draw points, rather 2 array. - how make these shapes
complete? since i'm looping through points, first , last cannot connect together, how can it? - can draw shape without giving specific points order?(something
convex hull?)
the code below doesn't use temporary variables xs , ys, direct tuple unpacking. add first point points list make shapes complete.
rectangle = [(0,0),(0,1),(1,1),(1,0)] hexagon = [(0,0),(0,1),(1,2),(2,1),(2,0),(1,-1)] l_shape = [(0,0),(0,3),(1,3),(1,1),(3,1),(3,0)] concave = [(0,0),(0,3),(1,3),(1,1),(2,1),(2,3),(3,3),(3,0)] points in [rectangle, hexagon, l_shape, concave]: plt.plot(*zip(*(points+points[:1])), marker='o') automin, automax = plt.xlim() plt.xlim(automin-0.5, automax+0.5) automin, automax = plt.ylim() plt.ylim(automin-0.5, automax+0.5) plt.show() provide answer alternative leekaiinthesky's post
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