python - change the format of a numpy array with no loops -


i have numpy array shape a.shape = (1,k*d)and want transform numpy array shape b.shape = (k*d,k) in each column

b[i,j] = a[i] if j<i+1

b[i,j] = 0 if not

for example:

k = 3 d= 2 **********  =  |a|   =>  b =  |a 0 0|      |b|            |b 0 0|      |c|            |0 c 0|      |d|            |0 d 0|      |e|            |0 0 e|      |f|            |0 0 f|

mainly, no loops!

what looking sequence of numpy-matrix operations lead desired result.

this reproduces example. can generalized other k , d

in [12]: a=np.arange(6)     in [13]: b=np.zeros((6,3)) in [14]: b[np.arange(6),np.arange(3).repeat(2)]=a  in [15]: b out[15]:  array([[ 0.,  0.,  0.],        [ 1.,  0.,  0.],        [ 0.,  2.,  0.],        [ 0.,  3.,  0.],        [ 0.,  0.,  4.],        [ 0.,  0.,  5.]])

the key column indexing repeats necessary number of times

in [16]: np.arange(3).repeat(2) out[16]: array([0, 0, 1, 1, 2, 2])

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