sed - Adding a comment character in most simple possible way -


i want search file specific string , place comment @ beginning of string. need answer avoids regex, global changes, , other fancy stuff.

i wrote line:

sed -i.bak '/permitrootlogin no/# permitrootlogin no/' ./sshd_config

but error:

sed: -e expression #1, char 21: comments don't accept addresses

i assume issue need escape # character, i'm not finding resources on how that, or mentioning it. i've tried various combinations of putting ^ or \ or \^ in front of # i'm jut not getting right.

please note intentionally repeating text replaced. simple possible solution question: how replace "xyx" "# xyz" in obvious possible way.

as indicated in comments @mlt , try adding s @ beginning sed command. straight comment:

s/permitrootlogin....

i see said you're intentionally repeating test replaced. if mean, want same, maybe consider grouping matched text. understand may have meant want hand typed. anyway, here how match grouped text , add comment character:

s/(permitrootlogin)/# \1/

the parens indicated matched text should consider group, \1 indicates want put matched group there.

i hope helpful. happy coding! leave comment if have questions.


Comments

Post a Comment

Popular posts from this blog

c++ - Difference between pre and post decrement in recursive function argument -

i have following sample code used pre-decrement void function(int c) { if(c == 0) { return; } else { cout << "dp" << c << endl; function(--c); cout << c << endl; return; } } this function give output input 4 : dp3 dp2 dp1 dp0 0 1 2 3 but when use post decrement void function(int c) { if(c == 0) { return; } else { cout << "dp" << c << endl; function(c--); cout << c << endl; return; } } output goes in infinite loop dp4 can explain me in detail why happens ? this happens because function(c--) called same value of c , when finishes c decremented. recursively called, hence called same value no chance of return , hit stack overflow error. assume this, int x = 1, y = 0; y = x++ result y == 1 , x == 2. if y = ++x , bot x , y 2.
Read more

php - Nothing but 'run(); ' when browsing to my local project, how do I fix this? -

i added new project. made mistake in projectname.conf file in sites-available apache2, led me reinstalling apache2. after reinstalling , re-enabling projects on every page of every project .. <body> run(); </body> .. i've run composer update, restarted service, restarted pc, checked config files, tried disabling new project. there nothing in error log, , access.log: 127.0.0.1 - - [15/may/2015:01:40:47 +0200] "get / http/1.1" 304 181 "-" "mozilla/5.0 (x11; ubuntu; linux x86_64; rv:38.0) gecko/20100101 firefox/38.0" maybe i'm forgetting apache2 reinstall? don't think did different last time installed it. looks haven't setup php correctly. take @ this great guide , maybe you're forgetting link php config apache2.
Read more

php - How can I echo out this array? -

i don't know how go grabbing data in variable , put foreach loop. class tree{ private $info = array( array('name'=>'jim','state'=>'nu','company'=>'nu','phone'=>array('cell'=>'5615111111','office'=>'5611111111'),'email'=>array('primary'=>'exs@example.com','ex@there.com')), array('name'=>'joe smith','city'=>'phoenix','phone'=>'4805551111','email'=>'jsmith@some_email.com'), array('name'=>'john doe','city'=>'chandler','company'=>'doe co.','email'=>array('jdoe@gmail.com','personal'=>'email@email.com'),'phone'=>'6025550002') ); } if you're inside of class, can access private variable using $this->variablename . example, i...
Read more