python - Multiprocessing pool not working in user defined function -


i wanted implement multiprocessing pool. if bug or mistake not able so. pooling works numpy function while user defined function runs error. 

import numpy >>> import multiprocessing >>> p = multiprocessing.pool(5) >>> p.map(numpy.sqrt,range(50))  [0.0, 1.0, 1.4142135623730951, 1.7320508075688772, 2.0, 2.2360679774997898,     2.4494897427831779, 2.6457513110645907, 2.8284271247461903, 3.0, 3.1622776601683795, 3.3166247903553998, 3.4641016151377544, 3.6055512754639891, 3.7416573867739413, 3.872983346207417, 4.0, 4.1231056256176606, 4.2426406871192848, 4.358898943540674, 4.4721359549995796, 4.5825756949558398, 4.6904157598234297, 4.7958315233127191, 4.8989794855663558, 5.0, 5.0990195135927845, 5.196152422706632, 5.2915026221291814, 5.3851648071345037, 5.4772255750516612, 5.5677643628300215, 5.6568542494923806, 5.7445626465380286, 5.8309518948453007, 5.9160797830996161, 6.0, 6.0827625302982193, 6.164414002968976, 6.2449979983983983, 6.324555320336759, 6.4031242374328485, 6.4807406984078604, 6.5574385243020004, 6.6332495807107996, 6.7082039324993694, 6.7823299831252681, 6.8556546004010439, 6.9282032302755088, 7.0] >>> def f(x):       return x*x  >>> p.map(f, range(50)) exception in thread thread-2: traceback (most recent call last): file "c:\python27\lib\threading.py", line 530, in __bootstrap_inner self.run() file "c:\python27\lib\threading.py", line 483, in run self.__target(*self.__args, **self.__kwargs) file "c:\python27\lib\multiprocessing\pool.py", line 285, in _handle_tasks put(task) typeerror: expected string or unicode object, nonetype found

i thankful, if suggest.

move code .py script, , call python on it.

or if must use python interpreter directly, move f function definition module import (just numpy.sqrt)

it seems when poolworkers spawned, local function definitions (e.g. f, defined in interpreter console) not passed it, complains.


Comments

Post a Comment

Popular posts from this blog

c++ - Difference between pre and post decrement in recursive function argument -

i have following sample code used pre-decrement void function(int c) { if(c == 0) { return; } else { cout << "dp" << c << endl; function(--c); cout << c << endl; return; } } this function give output input 4 : dp3 dp2 dp1 dp0 0 1 2 3 but when use post decrement void function(int c) { if(c == 0) { return; } else { cout << "dp" << c << endl; function(c--); cout << c << endl; return; } } output goes in infinite loop dp4 can explain me in detail why happens ? this happens because function(c--) called same value of c , when finishes c decremented. recursively called, hence called same value no chance of return , hit stack overflow error. assume this, int x = 1, y = 0; y = x++ result y == 1 , x == 2. if y = ++x , bot x , y 2.
Read more

php - Nothing but 'run(); ' when browsing to my local project, how do I fix this? -

i added new project. made mistake in projectname.conf file in sites-available apache2, led me reinstalling apache2. after reinstalling , re-enabling projects on every page of every project .. <body> run(); </body> .. i've run composer update, restarted service, restarted pc, checked config files, tried disabling new project. there nothing in error log, , access.log: 127.0.0.1 - - [15/may/2015:01:40:47 +0200] "get / http/1.1" 304 181 "-" "mozilla/5.0 (x11; ubuntu; linux x86_64; rv:38.0) gecko/20100101 firefox/38.0" maybe i'm forgetting apache2 reinstall? don't think did different last time installed it. looks haven't setup php correctly. take @ this great guide , maybe you're forgetting link php config apache2.
Read more

php - How can I echo out this array? -

i don't know how go grabbing data in variable , put foreach loop. class tree{ private $info = array( array('name'=>'jim','state'=>'nu','company'=>'nu','phone'=>array('cell'=>'5615111111','office'=>'5611111111'),'email'=>array('primary'=>'exs@example.com','ex@there.com')), array('name'=>'joe smith','city'=>'phoenix','phone'=>'4805551111','email'=>'jsmith@some_email.com'), array('name'=>'john doe','city'=>'chandler','company'=>'doe co.','email'=>array('jdoe@gmail.com','personal'=>'email@email.com'),'phone'=>'6025550002') ); } if you're inside of class, can access private variable using $this->variablename . example, i...
Read more